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Electronic Devices question

2006 · Shift 0 · Q84
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Electronic Devices question

2006 · Shift 0 · Q84

JEE MainPhysicsElectronic DevicesMCQ+4 / −1
The circuit has two oppositively connected ideal diodes in parallel. What is the current following in the circuit? AIEEE 2006 Physics - Semiconductor Question 200 English
  1. A
    1.71A1.71A1.71A
  2. B
    2.00A2.00A2.00A
  3. C
    2.31A2.31A2.31A
  4. D
    1.33A1.33A1.33A
View written solutionFree

Correct answer: B

  1. Key idea about the diode pair

    Two ideal diodes connected in parallel but in opposite directions act like a two-way short circuit:

    • for any polarity, one diode becomes forward biased,
    • an ideal forward-biased diode has zero resistance / zero voltage drop.

    Hence, this diode combination behaves as a wire (short circuit) between its two terminals.

  2. Effect on the given circuit

    Therefore, the branch containing the oppositely connected ideal diodes offers no voltage drop.

    So the current in the circuit is determined only by the source voltage and the series resistance present in the circuit.

  3. Using Ohm's law

    From the circuit, the effective resistance is just the resistor in series, so I=VRI=\frac{V}{R}I=RV​

    Substituting the circuit values gives I=2.00 AI=2.00\,\text{A}I=2.00A

  4. Checking options

    • A: 1.71 A1.71\,\text{A}1.71A ❌
    • B: 2.00 A2.00\,\text{A}2.00A ✅
    • C: 2.31 A2.31\,\text{A}2.31A ❌
    • D: 1.33 A1.33\,\text{A}1.33A ❌

Therefore, the correct answer is Option B.

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