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Electromagnetic Waves question

2021 · 26 Feb · Shift 1 · Q70
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  5. /2021 · 26 Feb · Shift 1 · Q70

Electromagnetic Waves question

2021 · 26 Feb · Shift 1 · Q70

JEE MainPhysicsElectromagnetic WavesNumerical+4 / −1
A radiation is emitted by 1000W bulb and it generates an electric field and magnetic field at P, placed at a distance of 2m. The efficiency of the bulb is 1.25%. The value of peak electric field at P is x ×\times× 10 −-− 1 V/m. Value of x is ‾\underline{\hspace{2cm}}​. (Rounded off to the nearest integer) [Take ε0=8.85×10−12{\varepsilon _0} = 8.85 \times {10^{ - 12}}ε0​=8.85×10−12 C2N −-− 1 m −-− 2, c = 3×1083 \times {10^8}3×108 ms −-− 1]
Numerical answer
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