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Electromagnetic Waves question

2021 · 26 Aug · Shift 1 · Q64
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  5. /2021 · 26 Aug · Shift 1 · Q64

Electromagnetic Waves question

2021 · 26 Aug · Shift 1 · Q64

JEE MainPhysicsElectromagnetic WavesNumerical+4 / −1
The electric field in a plane electromagnetic wave is given by E→=200cos⁡[(0.5×103m)x−(1.5×1011rads×t)]Vmj^\overrightarrow E = 200\cos \left[ {\left( {{{0.5 \times {{10}^3}} \over m}} \right)x - \left( {1.5 \times {{10}^{11}}{{rad} \over s} \times t} \right)} \right]{V \over m}\widehat jE=200cos[(m0.5×103​)x−(1.5×1011srad​×t)]mV​j​. If this wave falls normally on a perfectly reflecting surface having an area of 100 cm2. If the radiation pressure exerted by the E.M. wave on the surface during a 10 minute exposure is x109Nm2{x \over {{{10}^9}}}{N \over {{m^2}}}109x​m2N​. Find the value of x .
Numerical answer
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