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Electromagnetic Waves question

2017 · 8 Apr · Shift 1 · Q52
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  5. /2017 · 8 Apr · Shift 1 · Q52

Electromagnetic Waves question

2017 · 8 Apr · Shift 1 · Q52

JEE MainPhysicsElectromagnetic WavesMCQ+4 / −1
Magnetic field in a plane electromagnetic wave is given by B→\overrightarrow BB= B0 sin (k x +ω\omegaω t) j^ T\widehat j\,Tj​T Expression for corresponding electric field will be : Where c is speed of light.
  1. A
    E→\overrightarrow EE= B0 c sin (k x +ω\omegaω t) k^\widehat kk V/m
  2. B
    E→\overrightarrow EE=B0c{{{B_0}} \over c}cB0​​ sin (k x +ω\omegaω t) k^\widehat kk V/m
  3. C
    E→\overrightarrow EE=−-− B0 c sin (kx +ω\omegaω t) k^\widehat kk V/m
  4. D
    E→\overrightarrow EE= B0 c sin (kx −ω-\omega−ω t) k^\widehat kk V/m
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