JEE MainPhysicsElectromagnetic WavesMCQ+4 / −1
Arrange the following electromagnetic radiations per quantum in the order of increasing energy : A : Blue light B : Yellow light C : X-ray D : Radiowave.
- AC, A, B, D
- BB, A, D, C
- CD, B, A, C
- DA, B, D, C
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Correct answer: C
- The energy of one quantum (one photon) of electromagnetic radiation is given by
where:
- = Planck's constant
- = frequency
- = wavelength
So, higher frequency means higher energy, and equivalently, smaller wavelength means higher energy.
- Now compare the given radiations:
- Radiowave (D): very low frequency, so lowest energy
- Yellow light (B): visible light, lower frequency than blue light
- Blue light (A): visible light, higher frequency than yellow light
- X-ray (C): very high frequency, so highest energy
Thus, the order of increasing energy is:
- Match with the options:
- A: ❌ decreasing mostly
- B: ❌ radiowave should come first
- C: ✅
- D: ❌ blue has more energy than yellow, not less
Therefore, the correct option is:
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