1. Given data

• Radius of coil: $r = 8.0\text{ cm} = 0.08\text{ m}$
• Number of turns: $N = 20$
• Angular speed: $\omega = 50\text{ rad s}^{-1}$
• Magnetic field: $B = 3.0 \times 10^{-2}\text{ T}$

2. Formula for maximum induced emf

For a coil rotating in a uniform magnetic field,

$e = N B A \omega \sin(\omega t)$

So the maximum emf is

$e_{\max} = N B A \omega$

where area of the circular coil is

$A = \pi r^2$

3. Calculate area

$A = \pi (0.08)^2 = \pi \times 0.0064 \approx 0.0201\text{ m}^2$

4. Calculate maximum emf

$e_{\max} = 20 \times 3.0\times 10^{-2} \times 0.0201 \times 50$

Now simplify step-by-step:

$20 \times 3.0\times 10^{-2} = 0.6$

$0.6 \times 0.0201 = 0.01206$

$0.01206 \times 50 = 0.603\text{ V}$

Thus,

$e_{\max} \approx 0.603\text{ V}$

5. Express in the required form

We need

$e_{\max} = (\text{number}) \times 10^{-2}\text{ V}$

Since

$0.603\text{ V} = 60.3 \times 10^{-2}\text{ V}$

Rounded to nearest integer:

$\boxed{60}$

6. Comparison with stored answer

Derived answer = $60$

Stored correct answer = $60$

Hence, the answer matches.