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Electromagnetic Induction question

2020 · 7 Jan · Shift 1 · Q63
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Electromagnetic Induction question

2020 · 7 Jan · Shift 1 · Q63

JEE MainPhysicsElectromagnetic InductionNumerical+4 / −1
A loop ABCDEFA of straight edges has six corner points A(0, 0, 0), B(5, 0, 0), C(5, 5, 0), D (0, 5, 0), E(0, 5, 5) and F(0, 0, 5). The magnetic field in this region is B→=(3i^+4k^)T\overrightarrow B = \left( {3\widehat i + 4\widehat k} \right)TB=(3i+4k)T . The quantity of flux through the loop ABCDEFA (in Wb) is ‾\underline{\hspace{2cm}}​.
Numerical answer
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