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Current Electricity question

2025 · 3 Apr · Shift 2 · Q73
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Current Electricity question

2025 · 3 Apr · Shift 2 · Q73

JEE MainPhysicsCurrent ElectricityNumerical+4 / −1
Two cells of emfs 1 V and 2 V and internal resistances 2Ω2 \Omega2Ω and 1Ω1 \Omega1Ω, respectively, are connected in series with an external resistance of 6Ω6 \Omega6Ω. The total current in the circuit is I1I_1I1​. Now the same two cells in parallel configuration are connected to same external resistance. In this case, the total current drawn is I2\mathrm{I}_2I2​. The value of (I1I2)\left(\frac{\mathrm{I}_1}{\mathrm{I}_2}\right)(I2​I1​​) is x3\frac{x}{3}3x​. The value of xxx is ‾\underline{\hspace{2cm}}​.
Numerical answer
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