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Current Electricity question

2025 · 2 Apr · Shift 1 · Q67
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Current Electricity question

2025 · 2 Apr · Shift 1 · Q67

JEE MainPhysicsCurrent ElectricityMCQ+4 / −1
The battery of a mobile phone is rated as 4.2 V,5800 mAh4.2 \mathrm{~V}, 5800 \mathrm{~mAh}4.2 V,5800 mAh. How much energy is stored ir it when fully charged?
  1. A
    87.7 kJ
  2. B
    43.8 kJ
  3. C
    48.7 kJ
  4. D
    24.4 kJ
View written solutionFree

Correct answer: A

  1. Given data

    • Battery voltage: V=4.2 VV = 4.2\,\text{V}V=4.2V
    • Battery capacity: 5800 mAh5800\,\text{mAh}5800mAh
  2. Convert mAh to Ah 5800 mAh=5.8 Ah5800\,\text{mAh} = 5.8\,\text{Ah}5800mAh=5.8Ah

  3. Use energy formula Electrical energy in watt-hour is: E=V×(Ah)E = V \times (\text{Ah})E=V×(Ah) E=4.2×5.8=24.36 WhE = 4.2 \times 5.8 = 24.36\,\text{Wh}E=4.2×5.8=24.36Wh

  4. Convert Wh to joules We know: 1 Wh=3600 J1\,\text{Wh} = 3600\,\text{J}1Wh=3600J Hence, E=24.36×3600=87696 JE = 24.36 \times 3600 = 87696\,\text{J}E=24.36×3600=87696J

  5. Convert to kJ E=87.696 kJ≈87.7 kJE = 87.696\,\text{kJ} \approx 87.7\,\text{kJ}E=87.696kJ≈87.7kJ

  6. Match with options The correct option is: A: 87.7 kJ\boxed{\text{A: }87.7\,\text{kJ}}A: 87.7kJ​

  7. Comparison with stored correct answer Stored correct answer: A

    My derived answer is also A, so they agree.

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