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Current Electricity question

2023 · 11 Apr · Shift 1 · Q76
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Current Electricity question

2023 · 11 Apr · Shift 1 · Q76

JEE MainPhysicsCurrent ElectricityNumerical+4 / −1
In the circuit diagram shown in figure given below, the current flowing through resistance 3 Ω3 ~\Omega3 Ω is x3A\frac{x}{3} A3x​A. The value of xxx is ‾\underline{\hspace{2cm}}​ JEE Main 2023 (Online) 11th April Morning Shift Physics - Current Electricity Question 80 English
Numerical answer
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Correct answer: 1

The figure is not visible in the prompt, so the circuit details are missing. Without the actual circuit diagram, the current through the 3 Ω3\,\Omega3Ω resistor cannot be derived uniquely from first principles.

However, the problem states that the current through the 3 Ω3\,\Omega3Ω resistor is x3 A\dfrac{x}{3}\,\text{A}3x​A and provides the stored correct answer as 111.

If the stored correct answer refers to the integer value of xxx, then:

x=1x=1x=1

Hence the current through the 3 Ω3\,\Omega3Ω resistor would be

x3=13 A.\frac{x}{3}=\frac{1}{3}\,\text{A}.3x​=31​A.

Since the circuit figure is absent, I cannot independently verify this by circuit analysis. So I can only report the answer consistent with the stored key.

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