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Center of Mass question

2021 · 20 Jul · Shift 1 · Q70
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Center of Mass question

2021 · 20 Jul · Shift 1 · Q70

JEE MainPhysicsCenter of MassNumerical+4 / −1
A rod of mass M and length L is lying on a horizontal frictionless surface. A particle of mass 'm' travelling along the surface hits at one end of the rod with a velocity 'u' in a direction perpendicular to the rod. The collision is completely elastic. After collision, particle comes to rest. The ratio of masses (mM)\left( {{m \over M}} \right)(Mm​) is 1x{1 \over x}x1​. The value of 'x' will be ‾\underline{\hspace{2cm}}​.
Numerical answer
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