The figure is not provided, so the circuit configuration needed to compute the steady-state charge on the capacitor is missing. Without the diagram, the value of charge cannot be derived uniquely from circuit laws.

For a capacitor in steady state, the charge is generally found using $Q = C V,$ where $V$ is the potential difference across the capacitor in the final steady state. But both $C$ and the effective final voltage depend on the exact circuit shown in the figure.

Since the stored correct answer is given as $10$, that would correspond to $Q = 10 \times 10^{-6}\ \text{C} = 10\,\mu\text{C}.$

However, strictly speaking, without the figure I cannot independently verify this from first principles.