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Capacitor question

2016 · 10 Apr · Shift 1 · Q64
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Capacitor question

2016 · 10 Apr · Shift 1 · Q64

JEE MainPhysicsCapacitorMCQ+4 / −1
Figure shows a network of capacitors where the numbers indicates capacitances in micro Farad. The value of capacitance C if the equivalent capacitance between point A and B is to be 1 μ\muμ F is : JEE Main 2016 (Online) 10th April Morning Slot Physics - Capacitor Question 132 English
  1. A
    3123 μF{{31} \over {23}}\,\mu F2331​μF
  2. B
    3223 μF{{32} \over {23}}\,\mu F2332​μF
  3. C
    3323 μF{{33} \over {23}}\,\mu F2333​μF
  4. D
    3423 μF{{34} \over {23}}\,\mu F2334​μF
View written solutionFree

Correct answer: B

The capacitor network figure is not visible in the prompt, so the exact topology of the circuit is missing. Without the actual arrangement of the capacitors between AAA and BBB, the value of CCC cannot be derived uniquely from first principles.

However, since this is an MCQ with given options and a stored correct answer, I can only compare against that stored answer.

  1. The required equivalent capacitance is given as Ceq=1 μF.C_{eq}=1\,\mu F.Ceq​=1μF.

  2. The unknown capacitor is one of the following: 3123 μF,3223 μF,3323 μF,3423 μF.\frac{31}{23}\,\mu F,\quad \frac{32}{23}\,\mu F,\quad \frac{33}{23}\,\mu F,\quad \frac{34}{23}\,\mu F.2331​μF,2332​μF,2333​μF,2334​μF.

  3. The stored correct answer is B, i.e. C=3223 μF.C=\frac{32}{23}\,\mu F.C=2332​μF.

Because the network diagram is absent, I cannot independently verify this by circuit reduction.

Hence, based only on the provided stored answer: C=3223 μF\boxed{C=\frac{32}{23}\,\mu F}C=2332​μF​

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