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Atoms and Nuclei question

2023 · 10 Apr · Shift 1 · Q60

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Atoms and Nuclei
2023 · 10 Apr · Shift 1 · Q60

Atoms and Nuclei question

2023 · 10 Apr · Shift 1 · Q60

JEE MainPhysicsAtoms and NucleiMCQ+4 / −1

The angular momentum for the electron in Bohr's orbit is L. If the electron is assumed to revolve in second orbit of hydrogen atom, then the change in angular momentum will be

A
L
B
$\frac{L}{2}$
C
zero
D
2 L

View written solutionFree

Correct answer: A

In Bohr's model, the angular momentum of an electron in the $n^{\text{th}}$ orbit is quantized as

$L_n = n\frac{h}{2\pi} = n\hbar$

Let the angular momentum in the first orbit be given as $L$ .

So,

$L_1 = \hbar = L$

For the second orbit ( $n=2$ ), the angular momentum is

$L_2 = 2\hbar = 2L$

Hence, the change in angular momentum in going from the first orbit to the second orbit is

$\Delta L = L_2 - L_1 = 2L - L = L$

Therefore, the correct option is:

$\boxed{\text{A: } L}$

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