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Atoms and Nuclei question

2014 · Shift 0 · Q50
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  5. /2014 · Shift 0 · Q50

Atoms and Nuclei question

2014 · Shift 0 · Q50

JEE MainPhysicsAtoms and NucleiMCQ+4 / −1
Hydrogen (1H1)\left( {{}_1{H^1}} \right)(1​H1), Deuterium (1H2)\left( {{}_1{H^2}} \right)(1​H2), singly ionised Helium (2He4)+{\left( {{}_2H{e^4}} \right)^ + }(2​He4)+ and doubly ionised lithium (3Li6)++{\left( {{}_3L{i^6}} \right)^{ + + }}(3​Li6)++ all have one electron around the nucleus. Consider an electron transition from n=2n=2n=2 to n=1.n=1.n=1. If the wavelengths of emitted radiation are λ1,λ2,λ3{\lambda _1},{\lambda _2},{\lambda _3}λ1​,λ2​,λ3​ and λ4{\lambda _4}λ4​ respectively then approximately which one of the following is correct?
  1. A
    4λ1=2λ2=2λ3=λ44{\lambda _1} = 2{\lambda _2} = 2{\lambda _3} = {\lambda _4}4λ1​=2λ2​=2λ3​=λ4​
  2. B
    λ1=2λ2=2λ3=λ4{\lambda _1} = 2{\lambda _2} = 2{\lambda _3} = {\lambda _4}λ1​=2λ2​=2λ3​=λ4​
  3. C
    λ1=λ2=4λ3=9λ4{\lambda _1} = {\lambda _2} = 4{\lambda _3} = 9{\lambda _4}λ1​=λ2​=4λ3​=9λ4​
  4. D
    λ1=2λ2=3λ3=4λ4{\lambda _1} = 2{\lambda _2} = 3{\lambda _3} = 4{\lambda _4}λ1​=2λ2​=3λ3​=4λ4​
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