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3D Geometry · 2024 · 27 Jan · Shift 1

2 Mathematics questions from this JEE Main paper

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JEE Main
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2024 · 27 Jan · Shift 1
Mathematics
3D Geometry

3D Geometry · 2024 · 27 Jan · Shift 1

2 Mathematics questions from this JEE Main paper

Q37.The distance, of the point $(7, - 2, 11)$ from the line $\frac{x - 6}{1} = \frac{y - 4}{0} = \frac{z - 8}{3}$ along the line $\frac{x - 5}{2} = \frac{y - 1}{- 3} = \frac{z - 5}{6}$ , is :
Mathematics · 3D Geometry · MCQ
Q43.If the shortest distance between the lines $\frac{x - 4}{1} = \frac{y + 1}{2} = \frac{z}{- 3}$ and $\frac{x - λ}{2} = \frac{y + 1}{4} = \frac{z - 2}{- 5}$ is $\frac{6}{5}$ , then the sum of all possible values of $λ$ is :
Mathematics · 3D Geometry · MCQ