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Vector Algebra question

2025 · 29 Jan · Shift 1 · Q41
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  5. /2025 · 29 Jan · Shift 1 · Q41

Vector Algebra question

2025 · 29 Jan · Shift 1 · Q41

JEE MainMathematicsVector AlgebraMCQ+4 / −1
Let a⃗=2i^−j^+3k^, b⃗=3i^−5j^+k^\vec{a} = 2\hat{i} - \hat{j} + 3\hat{k}, \ \vec{b} = 3\hat{i} - 5\hat{j} + \hat{k}a=2i^−j^​+3k^, b=3i^−5j^​+k^ and c⃗\vec{c}c be a vector such that a⃗×c⃗=a⃗×b⃗=c⃗×b⃗\vec{a} \times \vec{c} = \vec{a} \times \vec{b} = \vec{c} \times \vec{b}a×c=a×b=c×b and (a⃗+c⃗)⋅(b⃗+c⃗)=168(\vec{a} + \vec{c}) \cdot (\vec{b} + \vec{c}) = 168(a+c)⋅(b+c)=168. Then the maximum value of ∣c⃗∣2|\vec{c}|^2∣c∣2 is :
  1. A
    77
  2. B
    154
  3. C
    308
  4. D
    462
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