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Vector Algebra question

2024 · 8 Apr · Shift 1 · Q53
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  5. /2024 · 8 Apr · Shift 1 · Q53

Vector Algebra question

2024 · 8 Apr · Shift 1 · Q53

JEE MainMathematicsVector AlgebraNumerical+4 / −1
Let a⃗=9i^−13j^+25k^,b⃗=3i^+7j^−13k^\vec{a}=9 \hat{i}-13 \hat{j}+25 \hat{k}, \vec{b}=3 \hat{i}+7 \hat{j}-13 \hat{k}a=9i^−13j^​+25k^,b=3i^+7j^​−13k^ and c⃗=17i^−2j^+k^\vec{c}=17 \hat{i}-2 \hat{j}+\hat{k}c=17i^−2j^​+k^ be three given vectors. If r⃗\vec{r}r is a vector such that r⃗×a⃗=(b⃗+c⃗)×a⃗\vec{r} \times \vec{a}=(\vec{b}+\vec{c}) \times \vec{a}r×a=(b+c)×a and r⃗⋅(b⃗−c⃗)=0\vec{r} \cdot(\vec{b}-\vec{c})=0r⋅(b−c)=0, then ∣593r⃗+67a⃗∣2(593)2\frac{|593 \vec{r}+67 \vec{a}|^2}{(593)^2}(593)2∣593r+67a∣2​ is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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