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Vector Algebra question

2017 · Shift 0 · Q35
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  5. /2017 · Shift 0 · Q35

Vector Algebra question

2017 · Shift 0 · Q35

JEE MainMathematicsVector AlgebraMCQ+4 / −1
Let a→=2i^+j^−2k^\overrightarrow a = 2\widehat i + \widehat j -2 \widehat ka=2i+j​−2k and b→=i^+j^\overrightarrow b = \widehat i + \widehat jb=i+j​. Let c→\overrightarrow cc be a vector such that ∣c→−a→∣=3\left| {\overrightarrow c - \overrightarrow a } \right| = 3​c−a​=3, ∣(a→×b→)×c→∣=3\left| {\left( {\overrightarrow a \times \overrightarrow b } \right) \times \overrightarrow c } \right| = 3​(a×b)×c​=3 and the angle between c→\overrightarrow cc and a→×b→\overrightarrow a \times \overrightarrow ba×b is 30∘30^\circ30∘. Then a→.c→\overrightarrow a .\overrightarrow ca.c is equal to :
  1. A
    2
  2. B
    5
  3. C
    18{1 \over 8}81​
  4. D
    258{{25} \over 8}825​
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