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Vector Algebra question

2012 · Shift 0 · Q44
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  5. /2012 · Shift 0 · Q44

Vector Algebra question

2012 · Shift 0 · Q44

JEE MainMathematicsVector AlgebraMCQ+4 / −1
Let ABCDABCDABCD be a parallelogram such that AB→=q→,AD→=p→\overrightarrow {AB} = \overrightarrow q ,\overrightarrow {AD} = \overrightarrow pAB=q​,AD=p​ and ∠BAD\angle BAD∠BAD be an acute angle. If r→\overrightarrow rr is the vector that coincide with the altitude directed from the vertex BBB to the side AD,AD,AD, then r→\overrightarrow rr is given by :
  1. A
    r→=3q→−3(p→.q→)(p→.p→)p→\overrightarrow r = 3\overrightarrow q - {{3\left( {\overrightarrow p .\overrightarrow q } \right)} \over {\left( {\overrightarrow p .\overrightarrow p } \right)}}\overrightarrow pr=3q​−(p​.p​)3(p​.q​)​p​
  2. B
    r→=−q→+(p→.q→)(p→.p→)p→\overrightarrow r = - \overrightarrow q + {{\left( {\overrightarrow p .\overrightarrow q } \right)} \over {\left( {\overrightarrow p .\overrightarrow p } \right)}}\overrightarrow pr=−q​+(p​.p​)(p​.q​)​p​
  3. C
    r⃗=q⃗−(p⃗.q⃗)(p⃗.p⃗)p⃗\vec r = \vec q - {{\left( {\vec p.\vec q} \right)} \over {\left( {\vec p.\vec p} \right)}}\vec pr=q​−(p​.p​)(p​.q​)​p​
  4. D
    r→=−3q→−3(p→.q→)(p→.p→)\overrightarrow r = - 3\overrightarrow q - {{3\left( {\overrightarrow p .\overrightarrow q } \right)} \over {\left( {\overrightarrow p .\overrightarrow p } \right)}}r=−3q​−(p​.p​)3(p​.q​)​
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