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Trigonometric Ratio and Identites question

2025 · 29 Jan · Shift 2 · Q40
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Trigonometric Ratio and Identites question

2025 · 29 Jan · Shift 2 · Q40

JEE MainMathematicsTrigonometric Ratio and IdentitesMCQ+4 / −1
If sin⁡x+sin⁡2x=1\sin x + \sin^2 x = 1sinx+sin2x=1, x∈(0,π2)x \in \left(0, \frac{\pi}{2}\right)x∈(0,2π​), then (cos⁡12x+tan⁡12x)+3(cos⁡10x+tan⁡10x+cos⁡8x+tan⁡8x)+(cos⁡6x+tan⁡6x)(\cos^{12} x + \tan^{12} x) + 3(\cos^{10} x + \tan^{10} x + \cos^8 x + \tan^8 x) + (\cos^6 x + \tan^6 x)(cos12x+tan12x)+3(cos10x+tan10x+cos8x+tan8x)+(cos6x+tan6x) is equal to:
  1. A
    3
  2. B
    4
  3. C
    2
  4. D
    1
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