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Trigonometric Ratio and Identites question

2024 · 1 Feb · Shift 1 · Q34
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  5. /2024 · 1 Feb · Shift 1 · Q34

Trigonometric Ratio and Identites question

2024 · 1 Feb · Shift 1 · Q34

JEE MainMathematicsTrigonometric Ratio and IdentitesMCQ+4 / −1
If tan⁡A=1x(x2+x+1),tan⁡B=xx2+x+1\tan \mathrm{A}=\frac{1}{\sqrt{x\left(x^2+x+1\right)}}, \tan \mathrm{B}=\frac{\sqrt{x}}{\sqrt{x^2+x+1}}tanA=x(x2+x+1)​1​,tanB=x2+x+1​x​​ and tan⁡C=(x−3+x−2+x−1)1/2,0<A,B,C<π2\tan \mathrm{C}=\left(x^{-3}+x^{-2}+x^{-1}\right)^{1 / 2}, 0\lt \mathrm{A}, \mathrm{B}, \mathrm{C}\lt \frac{\pi}{2}tanC=(x−3+x−2+x−1)1/2,0<A,B,C<2π​, then A+B\mathrm{A}+\mathrm{B}A+B is equal to :
  1. A
    C\mathrm{C}C
  2. B
    π−C\pi-Cπ−C
  3. C
    2π−C2 \pi-C2π−C
  4. D
    π2−C\frac{\pi}{2}-\mathrm{C}2π​−C
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