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Sets and Relations question

2024 · 27 Jan · Shift 2 · Q36
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  5. /2024 · 27 Jan · Shift 2 · Q36

Sets and Relations question

2024 · 27 Jan · Shift 2 · Q36

JEE MainMathematicsSets and RelationsMCQ+4 / −1
Let AAA and BBB be two finite sets with mmm and nnn elements respectively. The total number of subsets of the set AAA is 56 more than the total number of subsets of BBB. Then the distance of the point P(m,n)P(m, n)P(m,n) from the point Q(−2,−3)Q(-2,-3)Q(−2,−3) is :
  1. A
    8
  2. B
    10
  3. C
    4
  4. D
    6
View written solutionFree

Correct answer: B

  1. Use the formula for number of subsets

If a finite set has kkk elements, then the total number of subsets is: 2k2^k2k

So for sets AAA and BBB:

  • Number of subsets of A=2mA = 2^mA=2m
  • Number of subsets of B=2nB = 2^nB=2n

Given: 2m=2n+562^m = 2^n + 562m=2n+56 or 2m−2n=562^m - 2^n = 562m−2n=56

  1. Factor the expression

Assume m>nm>nm>n (since AAA has more subsets than BBB): 2n(2m−n−1)=562^n(2^{m-n}-1)=562n(2m−n−1)=56

Now, 56=23⋅756 = 2^3 \cdot 756=23⋅7

Since 2m−n−12^{m-n}-12m−n−1 is odd, it must divide the odd part of 565656, i.e. 777.

Thus: 2m−n−1=72^{m-n}-1=72m−n−1=7 2m−n=8=232^{m-n}=8=2^32m−n=8=23 So, m−n=3m-n=3m−n=3

Then: 2n⋅7=562^n \cdot 7 = 562n⋅7=56 2n=82^n=82n=8 n=3n=3n=3

Hence: m=n+3=6m=n+3=6m=n+3=6

So the point is: P(m,n)=(6,3)P(m,n)=(6,3)P(m,n)=(6,3)

  1. Find distance from Q(−2,−3)Q(-2,-3)Q(−2,−3)

Distance formula: PQ=(6−(−2))2+(3−(−3))2PQ=\sqrt{(6-(-2))^2+(3-(-3))^2}PQ=(6−(−2))2+(3−(−3))2​ =82+62=\sqrt{8^2+6^2}=82+62​ =64+36=\sqrt{64+36}=64+36​ =100=\sqrt{100}=100​ =10=10=10

  1. Check options

The correct option is: 10\boxed{10}10​ So, Option B is correct.

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