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Sequences and Series question

2021 · 31 Aug · Shift 2 · Q32
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  5. /2021 · 31 Aug · Shift 2 · Q32

Sequences and Series question

2021 · 31 Aug · Shift 2 · Q32

JEE MainMathematicsSequences and SeriesMCQ+4 / −1
Let a1, a2, a3, ..... be an A.P. If a1+a2+....+a10a1+a2+....+ap=100p2{{{a_1} + {a_2} + .... + {a_{10}}} \over {{a_1} + {a_2} + .... + {a_p}}} = {{100} \over {{p^2}}}a1​+a2​+....+ap​a1​+a2​+....+a10​​=p2100​, p eee 10, then a11a10{{{a_{11}}} \over {{a_{10}}}}a10​a11​​ is equal to :
  1. A
    1921{{19} \over {21}}2119​
  2. B
    100121{{100} \over {121}}121100​
  3. C
    2119{{21} \over {19}}1921​
  4. D
    121100{{121} \over {100}}100121​
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