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Quadratic Equation and Inequalities question

2025 · 23 Jan · Shift 1 · Q48
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  5. /2025 · 23 Jan · Shift 1 · Q48

Quadratic Equation and Inequalities question

2025 · 23 Jan · Shift 1 · Q48

JEE MainMathematicsQuadratic Equation and InequalitiesNumerical+4 / −1
If the equation a(b−c)x2+b(c−a)x+c(a−b)=0\mathrm{a}(\mathrm{b}-\mathrm{c}) \mathrm{x}^2+\mathrm{b}(\mathrm{c}-\mathrm{a}) \mathrm{x}+\mathrm{c}(\mathrm{a}-\mathrm{b})=0a(b−c)x2+b(c−a)x+c(a−b)=0 has equal roots, where a+c=15\mathrm{a}+\mathrm{c}=15a+c=15 and b=365\mathrm{b}=\frac{36}{5}b=536​, then a2+c2a^2+c^2a2+c2 is equal to ‾\underline{\hspace{2cm}}​
Numerical answer
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