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Permutations and Combinations question

2023 · 6 Apr · Shift 2 · Q39
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  5. /2023 · 6 Apr · Shift 2 · Q39

Permutations and Combinations question

2023 · 6 Apr · Shift 2 · Q39

JEE MainMathematicsPermutations and CombinationsNumerical+4 / −1
The number of 4-letter words, with or without meaning, each consisting of 2 vowels and 2 consonants, which can be formed from the letters of the word UNIVERSE without repetition is ‾\underline{\hspace{2cm}}​.
Numerical answer
View written solutionFree

Correct answer: 432

  1. Identify the letters in UNIVERSE

    The word UNIVERSE has 8 letters: U,N,I,V,E,R,S,EU, N, I, V, E, R, S, EU,N,I,V,E,R,S,E

    Since the letter EEE is repeated, the distinct letters available are: U,N,I,V,E,R,SU, N, I, V, E, R, SU,N,I,V,E,R,S

  2. Classify vowels and consonants

    Vowels among these are: U,I,EU, I, EU,I,E So, number of distinct vowels =3=3=3.

    Consonants are: N,V,R,SN, V, R, SN,V,R,S So, number of distinct consonants =4=4=4.

  3. Choose 2 vowels and 2 consonants

    Number of ways to choose 2 vowels from 3: (32)=3\binom{3}{2}=3(23​)=3

    Number of ways to choose 2 consonants from 4: (42)=6\binom{4}{2}=6(24​)=6

    Hence, total selections of letters: 3×6=183 \times 6 = 183×6=18

  4. Arrange the 4 chosen letters

    All chosen letters are distinct, so the number of 4-letter arrangements is: 4!=244! = 244!=24

  5. Total number of words

    18×24=43218 \times 24 = 43218×24=432

  6. Final answer

    The required number of 4-letter words is: 432\boxed{432}432​

  7. Comparison with stored answer

    Stored correct answer = 432432432.

    Our derived answer also equals 432432432, so it matches.

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