JEE MainMathematicsPermutations and CombinationsMCQ+4 / −1
Total number of four digit odd numbers that can be formed using 0, 1, 2, 3, 5, 7 (using repetition allowed) are :
- A216
- B375
- C400
- D720
View written solutionFree
Correct answer: D
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We need to form 4-digit odd numbers using the digits with repetition allowed.
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Conditions for a 4-digit odd number:
- The first digit cannot be .
- The last digit must be odd.
- Count choices position-wise.
First digit
Possible digits are . So, number of choices =
Last digit
To make the number odd, the last digit must be one of So, number of choices =
Middle two digits
For each of the 2 middle places, any of the 6 digits can be used since repetition is allowed:
So total choices for the middle two digits:
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Total number of such numbers:
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Therefore, the total number of four-digit odd numbers is
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Comparing with the stored correct answer:
- Stored correct answer: D
- Derived answer: D
Hence, the derived answer agrees with the stored answer.
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