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Parabola question

2021 · 20 Jul · Shift 2 · Q36
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  5. /2021 · 20 Jul · Shift 2 · Q36

Parabola question

2021 · 20 Jul · Shift 2 · Q36

JEE MainMathematicsParabolaMCQ+4 / −1
Let P be a variable point on the parabola y=4x2+1y = 4{x^2} + 1y=4x2+1. Then, the locus of the mid-point of the point P and the foot of the perpendicular drawn from the point P to the line y = x is :
  1. A
    (3x−y)2+(x−3y)+2=0{(3x - y)^2} + (x - 3y) + 2 = 0(3x−y)2+(x−3y)+2=0
  2. B
    2(3x−y)2+(x−3y)+2=02{(3x - y)^2} + (x - 3y) + 2 = 02(3x−y)2+(x−3y)+2=0
  3. C
    (3x−y)2+2(x−3y)+2=0{(3x - y)^2} + 2(x - 3y) + 2 = 0(3x−y)2+2(x−3y)+2=0
  4. D
    2(x−3y)2+(3x−y)+2=02{(x - 3y)^2} + (3x - y) + 2 = 02(x−3y)2+(3x−y)+2=0
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