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Matrices and Determinants question

2025 · 23 Jan · Shift 1 · Q44
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Matrices and Determinants question

2025 · 23 Jan · Shift 1 · Q44

JEE MainMathematicsMatrices and DeterminantsMCQ+4 / −1
If A,B,and⁡(adj⁡(A−1)+adj⁡(B−1))\mathrm{A}, \mathrm{B}, \operatorname{and}\left(\operatorname{adj}\left(\mathrm{A}^{-1}\right)+\operatorname{adj}\left(\mathrm{B}^{-1}\right)\right)A,B,and(adj(A−1)+adj(B−1)) are non-singular matrices of same order, then the inverse of A(adj⁡(A−1)+adj⁡(B−1))−1BA\left(\operatorname{adj}\left(A^{-1}\right)+\operatorname{adj}\left(B^{-1}\right)\right)^{-1} BA(adj(A−1)+adj(B−1))−1B, is equal to
  1. A
    AB−1∣A∣+BA−1∣B∣\frac{A B^{-1}}{|A|}+\frac{B A^{-1}}{|B|}∣A∣AB−1​+∣B∣BA−1​
  2. B
    adj⁡(B−1)+adj⁡(A−1)\operatorname{adj}\left(\mathrm{B}^{-1}\right)+\operatorname{adj}\left(\mathrm{A}^{-1}\right)adj(B−1)+adj(A−1)
  3. C
    AB−1+A−1 B\mathrm{AB}^{-1}+\mathrm{A}^{-1} \mathrm{~B}AB−1+A−1 B
  4. D
    1∣AB∣(adj⁡(B)+adj⁡(A))\frac{1}{|A B|}(\operatorname{adj}(B)+\operatorname{adj}(A))∣AB∣1​(adj(B)+adj(A))
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