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Logarithm question

2023 · 25 Jan · Shift 1 · Q43
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  5. /2023 · 25 Jan · Shift 1 · Q43

Logarithm question

2023 · 25 Jan · Shift 1 · Q43

JEE MainMathematicsLogarithmNumerical+4 / −1
Let S={α:log⁡2(92α−4+13)−log⁡2(52. 32α−4+1)=2}S = \left\{ {\alpha :{{\log }_2}({9^{2\alpha - 4}} + 13) - {{\log }_2}\left( {{5 \over 2}.\,{3^{2\alpha - 4}} + 1} \right) = 2} \right\}S={α:log2​(92α−4+13)−log2​(25​.32α−4+1)=2}. Then the maximum value of β\betaβ for which the equation x2−2(∑α∈sα)2x+∑α∈s(α+1)2β=0{x^2} - 2{\left( {\sum\limits_{\alpha \in s} \alpha } \right)^2}x + \sum\limits_{\alpha \in s} {{{(\alpha + 1)}^2}\beta = 0}x2−2(α∈s∑​α)2x+α∈s∑​(α+1)2β=0 has real roots, is ‾\underline{\hspace{2cm}}​.
Numerical answer
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