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Logarithm question

2021 · 20 Jul · Shift 2 · Q39
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  5. /2021 · 20 Jul · Shift 2 · Q39

Logarithm question

2021 · 20 Jul · Shift 2 · Q39

JEE MainMathematicsLogarithmNumerical+4 / −1
The number of solutions of the equation log⁡(x+1)(2x2+7x+5)+log⁡(2x+5)(x+1)2−4=0{\log _{(x + 1)}}(2{x^2} + 7x + 5) + {\log _{(2x + 5)}}{(x + 1)^2} - 4 = 0log(x+1)​(2x2+7x+5)+log(2x+5)​(x+1)2−4=0, x > 0, is :
Numerical answer
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