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Logarithm question

2020 · 9 Jan · Shift 1 · Q34
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  5. /2020 · 9 Jan · Shift 1 · Q34

Logarithm question

2020 · 9 Jan · Shift 1 · Q34

JEE MainMathematicsLogarithmNumerical+4 / −1
The number of distinct solutions of the equation log⁡12∣sin⁡x∣=2−log⁡12∣cos⁡x∣{\log _{{1 \over 2}}}\left| {\sin x} \right| = 2 - {\log _{{1 \over 2}}}\left| {\cos x} \right|log21​​∣sinx∣=2−log21​​∣cosx∣ in the interval [0, 2 π\piπ], is ‾\underline{\hspace{2cm}}​.
Numerical answer
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