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Limits Continuity and Differentiability question

2025 · 22 Jan · Shift 1 · Q44
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  5. /2025 · 22 Jan · Shift 1 · Q44

Limits Continuity and Differentiability question

2025 · 22 Jan · Shift 1 · Q44

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
If ∑r=1nTr=(2n−1)(2n+1)(2n+3)(2n+5)64\sum_{r=1}^n T_r=\frac{(2 n-1)(2 n+1)(2 n+3)(2 n+5)}{64}∑r=1n​Tr​=64(2n−1)(2n+1)(2n+3)(2n+5)​, then lim⁡n→∞∑r=1n(1Tr)\lim_{n \rightarrow \infty} \sum_{r=1}^n\left(\frac{1}{T_r}\right)limn→∞​∑r=1n​(Tr​1​) is equal to :
  1. A
    23\frac{2}{3}32​
  2. B
    13\frac{1}{3}31​
  3. C
    1
  4. D
    0
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