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Limits Continuity and Differentiability question

2025 · 22 Jan · Shift 2 · Q39
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  5. /2025 · 22 Jan · Shift 2 · Q39

Limits Continuity and Differentiability question

2025 · 22 Jan · Shift 2 · Q39

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
If lim⁡x→∞((e1−e)(1e−x1+x))x=α\lim_{x \rightarrow \infty}\left(\left(\frac{\mathrm{e}}{1-\mathrm{e}}\right)\left(\frac{1}{\mathrm{e}}-\frac{x}{1+x}\right)\right)^x=\alphalimx→∞​((1−ee​)(e1​−1+xx​))x=α, then the value of log⁡eα1+log⁡eα\frac{\log _{\mathrm{e}} \alpha}{1+\log _{\mathrm{e}} \alpha}1+loge​αloge​α​ equals :
  1. A
    e−2e^{-2}e−2
  2. B
    e2\mathrm{e}^2e2
  3. C
    eee
  4. D
    e−1e^{-1}e−1
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