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Limits Continuity and Differentiability question

2025 · 8 Apr · Shift 2 · Q36
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  5. /2025 · 8 Apr · Shift 2 · Q36

Limits Continuity and Differentiability question

2025 · 8 Apr · Shift 2 · Q36

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
Given below are two statements: Statement I: lim⁡x→0(tan⁡−1x+log⁡e1+x1−x−2xx5)=25\lim\limits_{x \to 0} \left( \frac{\tan^{-1} x + \log_e \sqrt{\frac{1+x}{1-x}} - 2x}{x^5} \right) = \frac{2}{5}x→0lim​(x5tan−1x+loge​1−x1+x​​−2x​)=52​ Statement II: lim⁡x→1(x21−x)=1e2\lim\limits_{x \to 1} \left( x^{\frac{2}{1-x}} \right) = \frac{1}{e^2}x→1lim​(x1−x2​)=e21​ In the light of the above statements, choose the correct answer from the options given below:
  1. A
    Statement I is false but Statement II is true
  2. B
    Both Statement I and Statement II are false
  3. C
    Both Statement I and Statement II are true
  4. D
    Statement I is true but Statement II is false
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