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Limits Continuity and Differentiability question

2021 · 24 Feb · Shift 1 · Q39

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JEE Main
Mathematics
Limits Continuity and Differentiability
2021 · 24 Feb · Shift 1 · Q39

Limits Continuity and Differentiability question

2021 · 24 Feb · Shift 1 · Q39

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1

\mathop {\lim }\limits_{n \to \infty } \tan \left\{ {\sum\limits_{r = 1}^n {{{\tan }^{ - 1}}\left( {{1 \over {1 + r + {r^2}}}} \right)} } \right\}

is equal to

\underline{\hspace{2cm}}

.

Numerical answer

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