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Limits Continuity and Differentiability question

2021 · 25 Jul · Shift 2 · Q41
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  5. /2021 · 25 Jul · Shift 2 · Q41

Limits Continuity and Differentiability question

2021 · 25 Jul · Shift 2 · Q41

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
Consider the function where P(x) is a polynomial such that P'' (x) is always a constant and P(3) = 9. If f(x) is continuous at x = 2, then P(5) is equal to ‾\underline{\hspace{2cm}}​.JEE Main 2021 (Online) 25th July Evening Shift Mathematics - Limits, Continuity and Differentiability Question 123 English
Numerical answer
View written solutionFree

Correct answer: 39

The question statement appears to have a missing expression for the function f(x)f(x)f(x) after the words “Consider the function where P(x)P(x)P(x) is a polynomial...”. Without the actual definition of f(x)f(x)f(x), the condition “f(x)f(x)f(x) is continuous at x=2x=2x=2” cannot be used directly.

However, we can still infer the intended structure from the given data and the stored answer.


1. Use the condition on P(x)P(x)P(x)

Given that P′′(x)P''(x)P′′(x) is always a constant, P(x)P(x)P(x) must be a polynomial of degree at most 222.

So let

P(x)=ax2+bx+c.P(x)=ax^2+bx+c.P(x)=ax2+bx+c.

Then

P′′(x)=2a,P''(x)=2a,P′′(x)=2a,

which is indeed a constant.

Also given:

P(3)=9.P(3)=9.P(3)=9.

So,

9a+3b+c=9.9a+3b+c=9. 9a+3b+c=9.

2. Use the continuity condition at x=2x=2x=2

Since the actual form of f(x)f(x)f(x) is missing from the question, the continuity condition must have been intended to give another relation involving P(2)P(2)P(2) or nearby values.

The stored correct answer is 393939, so let us check what that implies.

If

P(5)=39,P(5)=39,P(5)=39,

then from

P(5)=25a+5b+c,P(5)=25a+5b+c,P(5)=25a+5b+c,

and

P(3)=9a+3b+c=9,P(3)=9a+3b+c=9,P(3)=9a+3b+c=9,

subtracting,

P(5)−P(3)=16a+2b=30,P(5)-P(3)=16a+2b=30,P(5)−P(3)=16a+2b=30,

so

8a+b=15.8a+b=15.8a+b=15.

This is consistent with a quadratic polynomial and would arise naturally from one more linear condition coming from continuity at x=2x=2x=2.

Let us solve for a polynomial satisfying both P(3)=9P(3)=9P(3)=9 and P(5)=39P(5)=39P(5)=39.

Take

P(x)=x2+4x−12.P(x)=x^2+4x-12.P(x)=x2+4x−12.

Then

P′′(x)=2,P''(x)=2,P′′(x)=2,

which is constant,

P(3)=9+12−12=9,P(3)=9+12-12=9,P(3)=9+12−12=9,

and

P(5)=25+20−12=33,P(5)=25+20-12=33,P(5)=25+20−12=33,

not 393939.

Try the general quadratic instead. Since only one additional continuity relation is missing, the answer cannot be uniquely derived from the visible text alone. Therefore the problem statement as provided is incomplete.


3. Comparison with stored answer

Because the function definition is missing, a rigorous derivation of P(5)P(5)P(5) from the given visible data is impossible.

The stored correct answer is:

39.39.39.

Given the incompleteness of the question, I cannot verify it from first principles.

So I do not confidently agree with the stored answer based on the provided statement alone.


Conclusion

The question is incomplete because the definition of f(x)f(x)f(x) is missing. Hence P(5)P(5)P(5) cannot be uniquely determined from the visible information alone.

If the intended missing function expression is supplied, I can solve it exactly.

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