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Limits Continuity and Differentiability question

2021 · 16 Mar · Shift 1 · Q41
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  5. /2021 · 16 Mar · Shift 1 · Q41

Limits Continuity and Differentiability question

2021 · 16 Mar · Shift 1 · Q41

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
If lim⁡x→0aex−bcos⁡x+ce−xxsin⁡x=2\mathop {\lim }\limits_{x \to 0} {{a{e^x} - b\cos x + c{e^{ - x}}} \over {x\sin x}} = 2x→0lim​xsinxaex−bcosx+ce−x​=2, then a + b + c is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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