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Limits Continuity and Differentiability question

2021 · 18 Mar · Shift 1 · Q30
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  5. /2021 · 18 Mar · Shift 1 · Q30

Limits Continuity and Differentiability question

2021 · 18 Mar · Shift 1 · Q30

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
If lim⁡x→0sin⁡−1x−tan⁡−1x3x3\mathop {\lim }\limits_{x \to 0} {{{{\sin }^{ - 1}}x - {{\tan }^{ - 1}}x} \over {3{x^3}}}x→0lim​3x3sin−1x−tan−1x​ is equal to L, then the value of (6L + 1) is
  1. A
    16{1 \over 6}61​
  2. B
    12{1 \over 2}21​
  3. C
    6
  4. D
    2
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