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Limits Continuity and Differentiability question

2014 · Shift 0 · Q26
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  1. PYQ Library
  2. /JEE Main
  3. /Mathematics
  4. /Limits Continuity and Differentiability
  5. /2014 · Shift 0 · Q26

Limits Continuity and Differentiability question

2014 · Shift 0 · Q26

JEE MainMathematicsLimits Continuity and DifferentiabilityMCQ+4 / −1
lim⁡x→0sin⁡(πcos⁡2x)x2\mathop {\lim }\limits_{x \to 0} {{\sin \left( {\pi {{\cos }^2}x} \right)} \over {{x^2}}}x→0lim​x2sin(πcos2x)​ is equal to :
  1. A
    −π- \pi−π
  2. B
    π\piπ
  3. C
    π2{\pi \over 2}2π​
  4. D
    1
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