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Inverse Trigonometric Functions question

2025 · 8 Apr · Shift 2 · Q34
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  5. /2025 · 8 Apr · Shift 2 · Q34

Inverse Trigonometric Functions question

2025 · 8 Apr · Shift 2 · Q34

JEE MainMathematicsInverse Trigonometric FunctionsMCQ+4 / −1
The value of cot⁡−1(1+tan⁡2(2)−1tan⁡(2))−cot⁡−1(1+tan⁡2(12)+1tan⁡(12))\cot^{-1} \left( \frac{\sqrt{1 + \tan^2(2)} - 1}{\tan(2)} \right) - \cot^{-1} \left( \frac{\sqrt{1 + \tan^2\left(\frac{1}{2}\right)} + 1}{\tan\left(\frac{1}{2}\right)} \right)cot−1(tan(2)1+tan2(2)​−1​)−cot−1(tan(21​)1+tan2(21​)​+1​) is equal to
  1. A
    π−32\pi - \frac{3}{2}π−23​
  2. B
    π+52\pi + \frac{5}{2}π+25​
  3. C
    π−54\pi - \frac{5}{4}π−45​
  4. D
    π+32\pi + \frac{3}{2}π+23​
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