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Inverse Trigonometric Functions question

2024 · 29 Jan · Shift 2 · Q49
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Inverse Trigonometric Functions question

2024 · 29 Jan · Shift 2 · Q49

JEE MainMathematicsInverse Trigonometric FunctionsMCQ+4 / −1
Let x=mnx=\frac{m}{n}x=nm​ (m,nm, nm,n are co-prime natural numbers) be a solution of the equation cos⁡(2sin⁡−1x)=19\cos \left(2 \sin ^{-1} x\right)=\frac{1}{9}cos(2sin−1x)=91​ and let α,β(α>β)\alpha, \beta(\alpha \gt \beta)α,β(α>β) be the roots of the equation mx2−nx−m+n=0m x^2-n x-m+ n=0mx2−nx−m+n=0. Then the point (α,β)(\alpha, \beta)(α,β) lies on the line
  1. A
    3x−2y=−23 x-2 y=-23x−2y=−2
  2. B
    3x+2y=23 x+2 y=23x+2y=2
  3. C
    5x+8y=95 x+8 y=95x+8y=9
  4. D
    5x−8y=−95 x-8 y=-95x−8y=−9
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