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Inverse Trigonometric Functions question

2023 · 1 Feb · Shift 1 · Q23
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Inverse Trigonometric Functions question

2023 · 1 Feb · Shift 1 · Q23

JEE MainMathematicsInverse Trigonometric FunctionsMCQ+4 / −1
Let SSS be the set of all solutions of the equation cos⁡−1(2x)−2cos⁡−1(1−x2)=π,x∈[−12,12]\cos ^{-1}(2 x)-2 \cos ^{-1}\left(\sqrt{1-x^{2}}\right)=\pi, x \in\left[-\frac{1}{2}, \frac{1}{2}\right]cos−1(2x)−2cos−1(1−x2​)=π,x∈[−21​,21​]. Then ∑x∈S2sin⁡−1(x2−1)\sum_{x \in S} 2 \sin ^{-1}\left(x^{2}-1\right)x∈S∑​2sin−1(x2−1) is equal to :
  1. A
    π−2sin⁡−1(34)\pi-2 \sin ^{-1}\left(\frac{\sqrt{3}}{4}\right)π−2sin−1(43​​)
  2. B
    π−sin⁡−1(34)\pi-\sin ^{-1}\left(\frac{\sqrt{3}}{4}\right)π−sin−1(43​​)
  3. C
    −2π3\frac{-2 \pi}{3}3−2π​
  4. D
    None
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