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Inverse Trigonometric Functions question

2023 · 1 Feb · Shift 2 · Q37
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  5. /2023 · 1 Feb · Shift 2 · Q37

Inverse Trigonometric Functions question

2023 · 1 Feb · Shift 2 · Q37

JEE MainMathematicsInverse Trigonometric FunctionsMCQ+4 / −1
Let S={x∈R:0<x<1 and 2tan⁡−1(1−x1+x)=cos⁡−1(1−x21+x2)}S = \left\{ x \in R: 0 \lt x \lt 1 \text{ and } 2\tan^{-1}\left(\frac{1-x}{1+x}\right) = \cos^{-1}\left(\frac{1-x^2}{1+x^2}\right) \right\}S={x∈R:0<x<1 and 2tan−1(1+x1−x​)=cos−1(1+x21−x2​)}. If n(S)\mathrm{n(S)}n(S) denotes the number of elements in S\mathrm{S}S then :
  1. A
    n(S)=0\mathrm{n}(\mathrm{S})=0n(S)=0
  2. B
    n(S)=1\mathrm{n}(\mathrm{S})=1n(S)=1 and only one element in S\mathrm{S}S is less than 12\frac{1}{2}21​.
  3. C
    n(S)=1\mathrm{n}(\mathrm{S})=1n(S)=1 and the elements in S\mathrm{S}S is more than 12\frac{1}{2}21​.
  4. D
    n(S)=1\mathrm{n}(\mathrm{S})=1n(S)=1 and the element in S\mathrm{S}S is less than 12\frac{1}{2}21​.
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