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Inverse Trigonometric Functions question

2022 · 26 Jul · Shift 2 · Q31
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  5. /2022 · 26 Jul · Shift 2 · Q31

Inverse Trigonometric Functions question

2022 · 26 Jul · Shift 2 · Q31

JEE MainMathematicsInverse Trigonometric FunctionsMCQ+4 / −1
If 0<x<120 \lt x \lt {1 \over {\sqrt 2 }}0<x<2​1​ and sin⁡−1xα=cos⁡−1xβ{{{{\sin }^{ - 1}}x} \over \alpha } = {{{{\cos }^{ - 1}}x} \over \beta }αsin−1x​=βcos−1x​, then the value of sin⁡(2παα+β)\sin \left( {{{2\pi \alpha } \over {\alpha + \beta }}} \right)sin(α+β2πα​) is :
  1. A
    4(1−x2)(1−2x2)4 \sqrt{\left(1-x^{2}\right)}\left(1-2 x^{2}\right)4(1−x2)​(1−2x2)
  2. B
    4x(1−x2)(1−2x2)4 x \sqrt{\left(1-x^{2}\right)}\left(1-2 x^{2}\right)4x(1−x2)​(1−2x2)
  3. C
    2x(1−x2)(1−4x2)2 x \sqrt{\left(1-x^{2}\right)}\left(1-4 x^{2}\right)2x(1−x2)​(1−4x2)
  4. D
    4(1−x2)(1−4x2)4 \sqrt{\left(1-x^{2}\right)}\left(1-4 x^{2}\right)4(1−x2)​(1−4x2)
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