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Inverse Trigonometric Functions question

2022 · 27 Jul · Shift 1 · Q39
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Inverse Trigonometric Functions question

2022 · 27 Jul · Shift 1 · Q39

JEE MainMathematicsInverse Trigonometric FunctionsNumerical+4 / −1
For k∈Rk \in \mathbb{R}k∈R, let the solutions of the equation cos⁡(sin⁡−1(xcot⁡(tan⁡−1(cos⁡(sin⁡−1x)))))=k,0<∣x∣<12\cos \left(\sin ^{-1}\left(x \cot \left(\tan ^{-1}\left(\cos \left(\sin ^{-1} x\right)\right)\right)\right)\right)=k, 0\lt |x|\lt \frac{1}{\sqrt{2}}cos(sin−1(xcot(tan−1(cos(sin−1x)))))=k,0<∣x∣<2​1​ be α\alphaα and β\betaβ, where the inverse trigonometric functions take only principal values. If the solutions of the equation x2−bx−5=0x^{2}-b x-5=0x2−bx−5=0 are 1α2+1β2\frac{1}{\alpha^{2}}+\frac{1}{\beta^{2}}α21​+β21​ and αβ\frac{\alpha}{\beta}βα​, then bk2\frac{b}{k^{2}}k2b​ is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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