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Inverse Trigonometric Functions question

2022 · 25 Jul · Shift 2 · Q45
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Inverse Trigonometric Functions question

2022 · 25 Jul · Shift 2 · Q45

JEE MainMathematicsInverse Trigonometric FunctionsNumerical+4 / −1
Let x=sin⁡(2tan⁡−1α)x = \sin (2{\tan ^{ - 1}}\alpha )x=sin(2tan−1α) and y=sin⁡(12tan⁡−143)y = \sin \left( {{1 \over 2}{{\tan }^{ - 1}}{4 \over 3}} \right)y=sin(21​tan−134​). If S={a∈R:y2=1−x}S = \{ a \in R:{y^2} = 1 - x\}S={a∈R:y2=1−x}, then ∑α∈S16α3\sum\limits_{\alpha \in S}^{} {16{\alpha ^3}}α∈S∑​16α3 is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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