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Inverse Trigonometric Functions question

2020 · 2 Sep · Shift 1 · Q33
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  5. /2020 · 2 Sep · Shift 1 · Q33

Inverse Trigonometric Functions question

2020 · 2 Sep · Shift 1 · Q33

JEE MainMathematicsInverse Trigonometric FunctionsMCQ+4 / −1
The domain of the function f(x) = sin⁡−1(∣x∣+5x2+1){\sin ^{ - 1}}\left( {{{\left| x \right| + 5} \over {{x^2} + 1}}} \right)sin−1(x2+1∣x∣+5​) is (–∞\infty∞, -a]∪\cup∪[a, ∞\infty∞). Then a is equal to :
  1. A
    17−12{{\sqrt {17} - 1} \over 2}217​−1​
  2. B
    1+172{{1 + \sqrt {17} } \over 2}21+17​​
  3. C
    172+1{{\sqrt {17} } \over 2} + 1217​​+1
  4. D
    172{{\sqrt {17} } \over 2}217​​
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