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Inverse Trigonometric Functions question

2019 · 10 Apr · Shift 2 · Q31
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  5. /2019 · 10 Apr · Shift 2 · Q31

Inverse Trigonometric Functions question

2019 · 10 Apr · Shift 2 · Q31

JEE MainMathematicsInverse Trigonometric FunctionsMCQ+4 / −1
If cos⁡−1x−cos⁡−1y2=α{\cos ^{ - 1}}x - {\cos ^{ - 1}}{y \over 2} = \alphacos−1x−cos−12y​=α,where –1 ≤\le≤ x ≤\le≤ 1, – 2 ≤\le≤ y ≤\le≤ 2, x ≤y2\le {y \over 2}≤2y​, then for all x, y, 4x2 – 4xy cos α\alphaα + y2 is equal to :
  1. A
    4 sin2 α\alphaα
  2. B
    2 sin2 α\alphaα
  3. C
    4 sin2 α\alphaα - 2x2y2
  4. D
    4 cos2 α\alphaα + 2x2y2
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