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Indefinite Integrals question

2021 · 27 Aug · Shift 2 · Q41
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Indefinite Integrals question

2021 · 27 Aug · Shift 2 · Q41

JEE MainMathematicsIndefinite IntegralsNumerical+4 / −1
If ∫2ex+3e−x4ex+7e−xdx=114(ux+vlog⁡e(4ex+7e−x))+C\int {{{2{e^x} + 3{e^{ - x}}} \over {4{e^x} + 7{e^{ - x}}}}dx = {1 \over {14}}(ux + v{{\log }_e}(4{e^x} + 7{e^{ - x}})) + C}∫4ex+7e−x2ex+3e−x​dx=141​(ux+vloge​(4ex+7e−x))+C, where C is a constant of integration, then u + v is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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